0=-4.9x^2+29.4x

Solution for 0=-4.9x^2+29.4x equation:

0=-4.9x^2+29.4x

We move all terms to the left:

0-(-4.9x^2+29.4x)=0

We add all the numbers together, and all the variables

-(-4.9x^2+29.4x)=0

We get rid of parentheses

4.9x^2-29.4x=0

a = 4.9; b = -29.4; c = 0;
Δ = b2-4ac
Δ = -29.42-4·4.9·0
Δ = 864.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29.4)-\sqrt{864.36}}{2*4.9}=\frac{29.4-\sqrt{864.36}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29.4)+\sqrt{864.36}}{2*4.9}=\frac{29.4+\sqrt{864.36}}{9.8}
$